Mathématiques

Question

résoudre les equation suivantes 

8x = 12x +4
7x - ( 5x + 3 ) = 5 ( x - 3 ) + 2
7x + 1 = - 1 - x 
5x/8 - 3/10 = 7x/40
A = 3 ( 2w -6) - ( 3 - 5x )
B = ( 2a - 5 ) ( 3 - 4a ) - 2 ( 5 - a )
merci de votre aide 

2 Réponse

  • 8x-12x=4
    -4x=4
    4x/4 = 4/4
    x = 1
  • 8x = 12x +4
    8x -12x = +4
    -4x = 4
    x = 4/4
    x=1
    7x -(5x+3) = 5(x-3)+2
    7x -5x -3 = 5x -15 +2
    7x -5x -5x = +3 -15 +2
    -3x = -10
    x = -10/3
    7x +1 = -1 -x
    7x +x = -1 -1
    8x = -2
    x = -2/8 = -1/4
    5x/8 -3/10 = 7x/40
    5x/8 X10/10 -3/10 X 8/8 = 7x/40
    50x/80 -24/80 = 7x/40
    50x/80 -7x/40 = 24/80
    50x/80 -14x/80 = 24/80
    36x/80 = 24/80
    18x/40 = 12/40
    9x/20 = 6/20

    A =  3 ( 2w -6) - ( 3 - 5x )
    6w -18 -3 +5x
    6w -21 +5x
    B = ( 2a - 5 ) ( 3 - 4a ) - 2 ( 5 - a )
    6a -8a² -15 +20a -10 + 2a
    28a -8a² -25

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